In the figure, PQR and RST are isosceles triangles where PR = QR and RS = RT. Given that SU, TW and PY are straight lines, find
- ∠VZY
- ∠TUZ
(a)
∠PQR = ∠QPR = ∠RST = ∠RTS (Isosceles triangle)
∠RTS = ∠UTZ = 37° (Verticallly opposite angles)
∠WTZ
= 37° - 14°
= 23°
∠TVZ
= 180° - 108°
= 72° (Angles on a straight line)
∠VZY
= 72° + 23°
= 95° (Exterior angle of a triangle)
(b)
∠TUZ
= 95° - 37°
= 58° (Exterior angle of a triangle)
Answer(s): (a) 95°; (b) 58°