In the figure, HJK is parallel to LMN and LK cuts ∠JLM equally. Given that ∠HJL = 46° and ∠JPK = 104°, find
- ∠n
- ∠p
(a)
∠HJL = ∠JLM (Alternate angles)
∠n
= 46° ÷ 2
= 23°
(b)
∠JLP = ∠n = 23°
∠p
= 104° - 23°
= 81° (Exterior angle of a triangle)
Answer(s): (a) 23°; (b) 81°