In the figure, GHJ is parallel to KLM and KJ cuts ∠HKL equally. Given that ∠GHK = 58° and ∠HNJ = 116°, find
- ∠f
- ∠g
(a)
∠GHK = ∠HKL (Alternate angles)
∠f
= 58° ÷ 2
= 29°
(b)
∠HKN = ∠f = 29°
∠g
= 116° - 29°
= 87° (Exterior angle of a triangle)
Answer(s): (a) 29°; (b) 87°