In the figure, FGH is parallel to JKL and JH cuts ∠GJK equally. Given that ∠FGJ = 40° and ∠GMH = 118°, find
- ∠e
- ∠f
(a)
∠FGJ = ∠GJK (Alternate angles)
∠e
= 40° ÷ 2
= 20°
(b)
∠GJM = ∠e = 20°
∠f
= 118° - 20°
= 98° (Exterior angle of a triangle)
Answer(s): (a) 20°; (b) 98°