In the figure, ABC is parallel to DEF and DC cuts ∠BDE equally. Given that ∠ABD = 54° and ∠BGC = 113°, find
- ∠s
- ∠t
(a)
∠ABD = ∠BDE (Alternate angles)
∠s
= 54° ÷ 2
= 27°
(b)
∠BDG = ∠s = 27°
∠t
= 113° - 27°
= 86° (Exterior angle of a triangle)
Answer(s): (a) 27°; (b) 86°