In the figure, CDE is parallel to FGH and FE cuts ∠DFG equally. Given that ∠CDF = 58° and ∠DJE = 108°, find
- ∠v
- ∠w
(a)
∠CDF = ∠DFG (Alternate angles)
∠v
= 58° ÷ 2
= 29°
(b)
∠DFJ = ∠v = 29°
∠w
= 108° - 29°
= 79° (Exterior angle of a triangle)
Answer(s): (a) 29°; (b) 79°