In the figure, GHJ is parallel to KLM and KJ cuts ∠HKL equally. Given that ∠GHK = 52° and ∠HNJ = 108°, find
- ∠d
- ∠e
(a)
∠GHK = ∠HKL (Alternate angles)
∠d
= 52° ÷ 2
= 26°
(b)
∠HKN = ∠d = 26°
∠e
= 108° - 26°
= 82° (Exterior angle of a triangle)
Answer(s): (a) 26°; (b) 82°