In the figure, HJK is parallel to LMN and LK cuts ∠JLM equally. Given that ∠HJL = 58° and ∠JPK = 117°, find
- ∠s
- ∠t
(a)
∠HJL = ∠JLM (Alternate angles)
∠s
= 58° ÷ 2
= 29°
(b)
∠JLP = ∠s = 29°
∠t
= 117° - 29°
= 88° (Exterior angle of a triangle)
Answer(s): (a) 29°; (b) 88°