In the figure, MNP is parallel to QRS and QP cuts ∠NQR equally. Given that ∠MNQ = 56° and ∠NTP = 117°, find
- ∠y
- ∠z
(a)
∠MNQ = ∠NQR (Alternate angles)
∠y
= 56° ÷ 2
= 28°
(b)
∠NQT = ∠y = 28°
∠z
= 117° - 28°
= 89° (Exterior angle of a triangle)
Answer(s): (a) 28°; (b) 89°