In the figure, FGH is parallel to JKL and JH cuts ∠GJK equally. Given that ∠FGJ = 60° and ∠GMH = 107°, find
- ∠f
- ∠g
(a)
∠FGJ = ∠GJK (Alternate angles)
∠f
= 60° ÷ 2
= 30°
(b)
∠GJM = ∠f = 30°
∠g
= 107° - 30°
= 77° (Exterior angle of a triangle)
Answer(s): (a) 30°; (b) 77°