In the figure, MNP is parallel to QRS and QP cuts ∠NQR equally. Given that ∠MNQ = 44° and ∠NTP = 104°, find
- ∠n
- ∠p
(a)
∠MNQ = ∠NQR (Alternate angles)
∠n
= 44° ÷ 2
= 22°
(b)
∠NQT = ∠n = 22°
∠p
= 104° - 22°
= 82° (Exterior angle of a triangle)
Answer(s): (a) 22°; (b) 82°