In the figure, KLM is parallel to NPQ and NM cuts ∠LNP equally. Given that ∠KLN = 60° and ∠LRM = 105°, find
- ∠y
- ∠z
(a)
∠KLN = ∠LNP (Alternate angles)
∠y
= 60° ÷ 2
= 30°
(b)
∠LNR = ∠y = 30°
∠z
= 105° - 30°
= 75° (Exterior angle of a triangle)
Answer(s): (a) 30°; (b) 75°