In the figure, HJK is parallel to LMN and LK cuts ∠JLM equally. Given that ∠HJL = 56° and ∠JPK = 118°, find
- ∠e
- ∠f
(a)
∠HJL = ∠JLM (Alternate angles)
∠e
= 56° ÷ 2
= 28°
(b)
∠JLP = ∠e = 28°
∠f
= 118° - 28°
= 90° (Exterior angle of a triangle)
Answer(s): (a) 28°; (b) 90°