In the figure, EFG is parallel to HJK and HG cuts ∠FHJ equally. Given that ∠EFH = 58° and ∠FLG = 106°, find
- ∠y
- ∠z
(a)
∠EFH = ∠FHJ (Alternate angles)
∠y
= 58° ÷ 2
= 29°
(b)
∠FHL = ∠y = 29°
∠z
= 106° - 29°
= 77° (Exterior angle of a triangle)
Answer(s): (a) 29°; (b) 77°