In the figure, KLM is parallel to NPQ and NM cuts ∠LNP equally. Given that ∠KLN = 56° and ∠LRM = 115°, find
- ∠m
- ∠n
(a)
∠KLN = ∠LNP (Alternate angles)
∠m
= 56° ÷ 2
= 28°
(b)
∠LNR = ∠m = 28°
∠n
= 115° - 28°
= 87° (Exterior angle of a triangle)
Answer(s): (a) 28°; (b) 87°