In the figure, EFG is parallel to HJK and HG cuts ∠FHJ equally. Given that ∠EFH = 54° and ∠FLG = 118°, find
- ∠f
- ∠g
(a)
∠EFH = ∠FHJ (Alternate angles)
∠f
= 54° ÷ 2
= 27°
(b)
∠FHL = ∠f = 27°
∠g
= 118° - 27°
= 91° (Exterior angle of a triangle)
Answer(s): (a) 27°; (b) 91°