In the figure, DEF is parallel to GHJ and GF cuts ∠EGH equally. Given that ∠DEG = 58° and ∠EKF = 100°, find
- ∠c
- ∠d
(a)
∠DEG = ∠EGH (Alternate angles)
∠c
= 58° ÷ 2
= 29°
(b)
∠EGK = ∠c = 29°
∠d
= 100° - 29°
= 71° (Exterior angle of a triangle)
Answer(s): (a) 29°; (b) 71°