In the figure, QRS is parallel to TUV and TS cuts ∠RTU equally. Given that ∠QRT = 44° and ∠RWS = 112°, find
- ∠n
- ∠p
(a)
∠QRT = ∠RTU (Alternate angles)
∠n
= 44° ÷ 2
= 22°
(b)
∠RTW = ∠n = 22°
∠p
= 112° - 22°
= 90° (Exterior angle of a triangle)
Answer(s): (a) 22°; (b) 90°