The figure shows a parallelogram. Find
- ∠r
- ∠q
- ∠p
(a)
∠TXV
= 180° - 38° - 74°
= 68° (Angles sum of triangle)
∠r = ∠TXV = 68° (Vertically opposite angles)
(b)
∠q = ∠TSV = 52° (Alternate angles)
(c)
∠VXT = ∠r = 68° (Vertically opposite angles)
∠p
= 68° - 52°
= 16° (Exterior angle of a triangle)
Answer(s): (a) 68°; (b) 52°; (c) 16°