The figure shows a parallelogram. Find
- ∠r
- ∠q
- ∠p
(a)
∠TXV
= 180° - 37° - 65°
= 78° (Angles sum of triangle)
∠r = ∠TXV = 78° (Vertically opposite angles)
(b)
∠q = ∠TSV = 54° (Alternate angles)
(c)
∠VXT = ∠r = 78° (Vertically opposite angles)
∠p
= 78° - 54°
= 24° (Exterior angle of a triangle)
Answer(s): (a) 78°; (b) 54°; (c) 24°