The figure shows a parallelogram. Find
- ∠r
- ∠q
- ∠p
(a)
∠TXV
= 180° - 34° - 79°
= 67° (Angles sum of triangle)
∠r = ∠TXV = 67° (Vertically opposite angles)
(b)
∠q = ∠TSV = 54° (Alternate angles)
(c)
∠VXT = ∠r = 67° (Vertically opposite angles)
∠p
= 67° - 54°
= 13° (Exterior angle of a triangle)
Answer(s): (a) 67°; (b) 54°; (c) 13°