The figure shows a parallelogram. Find
- ∠r
- ∠q
- ∠p
(a)
∠TXV
= 180° - 36° - 70°
= 74° (Angles sum of triangle)
∠r = ∠TXV = 74° (Vertically opposite angles)
(b)
∠q = ∠TSV = 53° (Alternate angles)
(c)
∠VXT = ∠r = 74° (Vertically opposite angles)
∠p
= 74° - 53°
= 21° (Exterior angle of a triangle)
Answer(s): (a) 74°; (b) 53°; (c) 21°