The figure shows a parallelogram. Find
- ∠h
- ∠g
- ∠f
(a)
∠JNK
= 180° - 38° - 66°
= 76° (Angles sum of triangle)
∠h = ∠JNK = 76° (Vertically opposite angles)
(b)
∠g = ∠JIK = 65° (Alternate angles)
(c)
∠KNJ = ∠h = 76° (Vertically opposite angles)
∠f
= 76° - 65°
= 11° (Exterior angle of a triangle)
Answer(s): (a) 76°; (b) 65°; (c) 11°