The figure shows a parallelogram. Find
- ∠q
- ∠p
- ∠n
(a)
∠SWT
= 180° - 41° - 63°
= 76° (Angles sum of triangle)
∠q = ∠SWT = 76° (Vertically opposite angles)
(b)
∠p = ∠SRT = 61° (Alternate angles)
(c)
∠TWS = ∠q = 76° (Vertically opposite angles)
∠n
= 76° - 61°
= 15° (Exterior angle of a triangle)
Answer(s): (a) 76°; (b) 61°; (c) 15°