The figure shows a parallelogram. Find
- ∠r
- ∠q
- ∠p
(a)
∠TXV
= 180° - 32° - 77°
= 71° (Angles sum of triangle)
∠r = ∠TXV = 71° (Vertically opposite angles)
(b)
∠q = ∠TSV = 56° (Alternate angles)
(c)
∠VXT = ∠r = 71° (Vertically opposite angles)
∠p
= 71° - 56°
= 15° (Exterior angle of a triangle)
Answer(s): (a) 71°; (b) 56°; (c) 15°