The figure shows a parallelogram. Find
- ∠c
- ∠b
- ∠a
(a)
∠EHF
= 180° - 45° - 71°
= 64° (Angles sum of triangle)
∠c = ∠EHF = 64° (Vertically opposite angles)
(b)
∠b = ∠EDF = 50° (Alternate angles)
(c)
∠FHE = ∠c = 64° (Vertically opposite angles)
∠a
= 64° - 50°
= 14° (Exterior angle of a triangle)
Answer(s): (a) 64°; (b) 50°; (c) 14°