The figure shows a parallelogram. Find
- ∠c
- ∠b
- ∠a
(a)
∠EHF
= 180° - 38° - 66°
= 76° (Angles sum of triangle)
∠c = ∠EHF = 76° (Vertically opposite angles)
(b)
∠b = ∠EDF = 65° (Alternate angles)
(c)
∠FHE = ∠c = 76° (Vertically opposite angles)
∠a
= 76° - 65°
= 11° (Exterior angle of a triangle)
Answer(s): (a) 76°; (b) 65°; (c) 11°