The figure shows a parallelogram. Find
- ∠r
- ∠q
- ∠p
(a)
∠TXV
= 180° - 40° - 63°
= 77° (Angles sum of triangle)
∠r = ∠TXV = 77° (Vertically opposite angles)
(b)
∠q = ∠TSV = 54° (Alternate angles)
(c)
∠VXT = ∠r = 77° (Vertically opposite angles)
∠p
= 77° - 54°
= 23° (Exterior angle of a triangle)
Answer(s): (a) 77°; (b) 54°; (c) 23°