In the figure, DF is parallel to HG and DJ is parallel to EK. DJH is a straight line, ∠DJK = 92°. ∠JDE = 98° and the sum of ∠EFG and ∠GHJ is 150°. Find
- ∠JKE
- ∠HGF
(a)
∠JKE
= 180° - 92°
= 88° (Interior angles)
(b)
∠HGF
= 360° - 150° - 98°
= 112° (Sum of angles in a quadrilateral)
Answer(s): (a) 88°; (b) 112°