In the figure, NQ is parallel to SR and NT is parallel to PU. NTS is a straight line, ∠NTU = 98°. ∠TNP = 92° and the sum of ∠PQR and ∠RST is 150°. Find
- ∠TUP
- ∠SRQ
(a)
∠TUP
= 180° - 98°
= 82° (Interior angles)
(b)
∠SRQ
= 360° - 150° - 92°
= 118° (Sum of angles in a quadrilateral)
Answer(s): (a) 82°; (b) 118°