In the figure, AC is parallel to ED and AF is parallel to BG. AFE is a straight line, ∠AFG = 105°. ∠FAB = 102° and the sum of ∠BCD and ∠DEF is 154°. Find
- ∠FGB
- ∠EDC
(a)
∠FGB
= 180° - 105°
= 75° (Interior angles)
(b)
∠EDC
= 360° - 154° - 102°
= 104° (Sum of angles in a quadrilateral)
Answer(s): (a) 75°; (b) 104°