In the figure, JL is parallel to NM and JP is parallel to KQ. JPN is a straight line, ∠JPQ = 103°. ∠PJK = 102° and the sum of ∠KLM and ∠MNP is 148°. Find
- ∠PQK
- ∠NML
(a)
∠PQK
= 180° - 103°
= 77° (Interior angles)
(b)
∠NML
= 360° - 148° - 102°
= 110° (Sum of angles in a quadrilateral)
Answer(s): (a) 77°; (b) 110°