In the figure, FH is parallel to KJ and FL is parallel to GM. FLK is a straight line, ∠FLM = 104°. ∠LFG = 96° and the sum of ∠GHJ and ∠JKL is 150°. Find
- ∠LMG
- ∠KJH
(a)
∠LMG
= 180° - 104°
= 76° (Interior angles)
(b)
∠KJH
= 360° - 150° - 96°
= 114° (Sum of angles in a quadrilateral)
Answer(s): (a) 76°; (b) 114°