In the figure, DF is parallel to HG and DJ is parallel to EK. DJH is a straight line, ∠DJK = 103°. ∠JDE = 103° and the sum of ∠EFG and ∠GHJ is 159°. Find
- ∠JKE
- ∠HGF
(a)
∠JKE
= 180° - 103°
= 77° (Interior angles)
(b)
∠HGF
= 360° - 159° - 103°
= 98° (Sum of angles in a quadrilateral)
Answer(s): (a) 77°; (b) 98°