In the figure, NQ is parallel to SR and NT is parallel to PU. NTS is a straight line, ∠NTU = 105°. ∠TNP = 99° and the sum of ∠PQR and ∠RST is 143°. Find
- ∠TUP
- ∠SRQ
(a)
∠TUP
= 180° - 105°
= 75° (Interior angles)
(b)
∠SRQ
= 360° - 143° - 99°
= 118° (Sum of angles in a quadrilateral)
Answer(s): (a) 75°; (b) 118°