In the figure, AC is parallel to ED and AF is parallel to BG. AFE is a straight line, ∠AFG = 93°. ∠FAB = 96° and the sum of ∠BCD and ∠DEF is 145°. Find
- ∠FGB
- ∠EDC
(a)
∠FGB
= 180° - 93°
= 87° (Interior angles)
(b)
∠EDC
= 360° - 145° - 96°
= 119° (Sum of angles in a quadrilateral)
Answer(s): (a) 87°; (b) 119°