In the figure, PR is parallel to TS and PU is parallel to QV. PUT is a straight line, ∠PUV = 95°. ∠UPQ = 95° and the sum of ∠QRS and ∠STU is 151°. Find
- ∠UVQ
- ∠TSR
(a)
∠UVQ
= 180° - 95°
= 85° (Interior angles)
(b)
∠TSR
= 360° - 151° - 95°
= 114° (Sum of angles in a quadrilateral)
Answer(s): (a) 85°; (b) 114°