In the figure, TV is parallel to XW and TY is parallel to UZ. TYX is a straight line, ∠TYZ = 103°. ∠YTU = 105° and the sum of ∠UVW and ∠WXY is 143°. Find
- ∠YZU
- ∠XWV
(a)
∠YZU
= 180° - 103°
= 77° (Interior angles)
(b)
∠XWV
= 360° - 143° - 105°
= 112° (Sum of angles in a quadrilateral)
Answer(s): (a) 77°; (b) 112°