In the figure, AC is parallel to ED and AF is parallel to BG. AFE is a straight line, ∠AFG = 95°. ∠FAB = 102° and the sum of ∠BCD and ∠DEF is 155°. Find
- ∠FGB
- ∠EDC
(a)
∠FGB
= 180° - 95°
= 85° (Interior angles)
(b)
∠EDC
= 360° - 155° - 102°
= 103° (Sum of angles in a quadrilateral)
Answer(s): (a) 85°; (b) 103°