In the figure, KM is parallel to PN and KQ is parallel to LR. KQP is a straight line, ∠KQR = 95°. ∠QKL = 98° and the sum of ∠LMN and ∠NPQ is 142°. Find
- ∠QRL
- ∠PNM
(a)
∠QRL
= 180° - 95°
= 85° (Interior angles)
(b)
∠PNM
= 360° - 142° - 98°
= 120° (Sum of angles in a quadrilateral)
Answer(s): (a) 85°; (b) 120°