In the figure, BD is parallel to FE and BG is parallel to CH. BGF is a straight line, ∠BGH = 95°. ∠GBC = 93° and the sum of ∠CDE and ∠EFG is 151°. Find
- ∠GHC
- ∠FED
(a)
∠GHC
= 180° - 95°
= 85° (Interior angles)
(b)
∠FED
= 360° - 151° - 93°
= 116° (Sum of angles in a quadrilateral)
Answer(s): (a) 85°; (b) 116°