In the figure, BD is parallel to FE and BG is parallel to CH. BGF is a straight line, ∠BGH = 96°. ∠GBC = 97° and the sum of ∠CDE and ∠EFG is 146°. Find
- ∠GHC
- ∠FED
(a)
∠GHC
= 180° - 96°
= 84° (Interior angles)
(b)
∠FED
= 360° - 146° - 97°
= 117° (Sum of angles in a quadrilateral)
Answer(s): (a) 84°; (b) 117°