In the figure, NQ is parallel to SR and NT is parallel to PU. NTS is a straight line, ∠NTU = 102°. ∠TNP = 94° and the sum of ∠PQR and ∠RST is 157°. Find
- ∠TUP
- ∠SRQ
(a)
∠TUP
= 180° - 102°
= 78° (Interior angles)
(b)
∠SRQ
= 360° - 157° - 94°
= 109° (Sum of angles in a quadrilateral)
Answer(s): (a) 78°; (b) 109°