In the figure, MNPQ is a parallelogram. O is the centre of the circle. Find
- ∠MQP
- ∠MNQ
(a)
∠ONQ = ∠NQO = 43° (Angle properties within a circle)
∠QON
= 180° - 43° - 43°
= 94° (Angles sum of triangle)
∠OMN + ∠ONM = ∠NOQ (Exterior angle of a triangle)
∠OMN = ∠ONM (Isosceles triangle, OM = ON)
∠OMN
= 94° ÷ 2
= 47° (Exterior angle of a triangle)
∠MQP
= 180° - 47°
= 133° (Interior angles)
(b)
∠MNQ
= 180° - 47° - 43°
= 90° (Angle sum of triangles)
Answer(s): (a) 133°; (b) 90°