JKLM is a rhombus. JMN is an equilateral triangle. Find
- ∠NJK
- ∠JKM
(a)
∠NJM
= 180° ÷ 3
= 60° (Equilateral triangle)
∠KJM = ∠KLM = 112° (Rhombus)
∠NJK
= 112° + 60°
= 172°
(b)
∠JKM
= (180° - 112°) ÷ 2
= 34° (Isosceles triangle)
Answer(s): (a) 172°; (b) 34°