HJKL is a rhombus. HLM is an equilateral triangle. Find
- ∠MHJ
- ∠HJL
(a)
∠MHL
= 180° ÷ 3
= 60° (Equilateral triangle)
∠JHL = ∠JKL = 106° (Rhombus)
∠MHJ
= 106° + 60°
= 166°
(b)
∠HJL
= (180° - 106°) ÷ 2
= 37° (Isosceles triangle)
Answer(s): (a) 166°; (b) 37°