KLMN is a rhombus. KNP is an equilateral triangle. Find
- ∠PKL
- ∠KLN
(a)
∠PKN
= 180° ÷ 3
= 60° (Equilateral triangle)
∠LKN = ∠LMN = 106° (Rhombus)
∠PKL
= 106° + 60°
= 166°
(b)
∠KLN
= (180° - 106°) ÷ 2
= 37° (Isosceles triangle)
Answer(s): (a) 166°; (b) 37°