KLMN is a rhombus. KNP is an equilateral triangle. Find
- ∠PKL
- ∠KLN
(a)
∠PKN
= 180° ÷ 3
= 60° (Equilateral triangle)
∠LKN = ∠LMN = 110° (Rhombus)
∠PKL
= 110° + 60°
= 170°
(b)
∠KLN
= (180° - 110°) ÷ 2
= 35° (Isosceles triangle)
Answer(s): (a) 170°; (b) 35°