PQRS is a rhombus. PST is an equilateral triangle. Find
- ∠TPQ
- ∠PQS
(a)
∠TPS
= 180° ÷ 3
= 60° (Equilateral triangle)
∠QPS = ∠QRS = 112° (Rhombus)
∠TPQ
= 112° + 60°
= 172°
(b)
∠PQS
= (180° - 112°) ÷ 2
= 34° (Isosceles triangle)
Answer(s): (a) 172°; (b) 34°