EFGH is a rhombus. EHJ is an equilateral triangle. Find
- ∠JEF
- ∠EFH
(a)
∠JEH
= 180° ÷ 3
= 60° (Equilateral triangle)
∠FEH = ∠FGH = 106° (Rhombus)
∠JEF
= 106° + 60°
= 166°
(b)
∠EFH
= (180° - 106°) ÷ 2
= 37° (Isosceles triangle)
Answer(s): (a) 166°; (b) 37°